如何检查二维数组是否连续具有三个相同的值

Question

我试图找出如何检查二维数组是否连续包含 3 个相同的值。此二维数组将由用户生成，因此用于检查的函数必须是动态的。例如，假设用户输入 4x4。结果会是这样  let arr=[    [" "," "," "," "],    [" "," "," "," "],    [" "," "," "," "],    [" "," "," "," "]  ]让我向该数组添加一些值  let arr=[    [" "," ","x","x"],    ["x","x","x"," "],    [" "," "," "," "],    [" "," "," "," "]  ]我试图用这个函数来解决这个问题，但昨天我注意到它不适合。  function checkArray(arr){    for(let i=0;i<arr.length;i++){      let count = 0;      for(let j=0;j<arr[i].length;j++){        if(arr[i][j] === 'x'){          count++;        }        if(count === 3 ){          console.log('x wins')        }      }    }  }    console.log(checkArray(arr)) //count will be 3 and console.logs 'x wins'.此时此刻，我认为一切正常，直到我尝试像这样填充数组。如您所见，没有连续三个 X（我的意思是它们不是这样的 - x,x,x），它们之间有一个空格。  let arr=[    [" "," ","x","x"],    ["x","x"," ","x"],    [" "," "," "," "],    [" "," "," "," "]  ]所以不应该满足条件并且函数不应该是 console.log('w wins')。但确实如此。我解决这个问题的方法适用于整行，而不仅仅是连续 3 个 (x,x,x)。我希望我已经解释清楚了。谢谢你的建议。

Answer 1

如果您没有获得 . ，则需要重置计数'x'。

function checkArray(arr) {

  for (let i = 0; i < arr.length; i++) {

    let count = 0;

    for (let j = 0; j < arr[i].length; j++) {

      if (arr[i][j] === 'x') {

        count++;

        if (count === 3) {                    // place check after incrementing

          console.log('x wins')

          return true;

        }

      } else {

        count = 0;                            // reset

      }

    }

  }

  return false;

}

let arr = [

  [" ", " ", "x", "x"],

  ["x", "x", " ", "x"],

  [" ", " ", " ", " "],

  [" ", " ", " ", " "]

]

console.log(checkArray(arr));