如何判断一个数是否是二进制数？

Question

my_l1:str = "0101011"我执行这段代码：for character in my_l1:    if character != '0' and character != '1':       print (f"{my_l1} is not a binary number")    else:       print(f"{my_l1} is a binary number")我得到这个输出：0101011 is a binary number0101011 is a binary number0101011 is a binary number0101011 is a binary number0101011 is a binary number0101011 is a binary number0101011 is a binary number如何获得像这样的单行输出？0101011 is a binary number.

Answer 1

您可以添加break和for..else。break将结束循环。

my_l1:str = "0101011"

for character in my_l1:

    if character != '0' and character != '1':

       print (f"{my_l1} is not a binary number")

       break

else:

    print (f"{my_l1} is a binary number")

印刷：

  0101011 is a binary number.

您可以使用以下方法重写代码all()：

my_l1:str = "0101011"

if all(ch=='0' or ch=='1' for ch in my_l1):

    print (f"{my_l1} is a binary number")

else:

    print (f"{my_l1} is not a binary number")

Answer 2

 my_l1:str = "0101011"

 isBinary=True ## We Assume it's True (i.e, the number is a binary) until we prove to 

               ## the contrary, so this boolean variable is used to check (if binary 

               ## or not)

 for character in my_l1:

        if character != '0' and character != '1':

                  sBinary=False ## once we find a number in the list my_l1 different 

                                ## than "0" and "1"  it is not necessary to continue 

                                ## looping through the list, because the number is not 

                                ## a binary anymore, so we break in order to consume 

                                ## time

                  break

 

  if isBinary: ## i.e, if isBinary==True then do :

          print (f"{my_l1} is a binary number")

  else:

          print(f"{my_l1} is not a binary number")

 

Answer 3

尝试这个：

def isBinary(num: str):

    for i in num:

        if i not in ["0","1"]:

            return False

    return True

if isBinary("000101") == True:

    print("000101 is binary")