根据其他字典的值对字典的值进行排序

Question

我有一本看起来像这样的字典..results = {'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000'], 'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'], 'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'], 'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'], 'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003']}我还有另一本字典，有这样的分数。score ={'agunii2035': [4, 4, 1, 3], 'agunii3007': [4, 3, 3, 1], 'agunii2006': [4, 3, 2, 2], 'agunii2003': [1, 3, 2, 1], 'agunii3000': [3, 1, 2, 1]}我想根据“分数”字典的值对“结果”字典的值进行排序。例如，对于键“agunii2035”，分数字典具有值 [ 4,4,1,3]。因此，我想对“结果”字典的值进行排序，以使用相同的键而['agunii3007', 'agunii2006', 'agunii3000','agunii2003']不是 ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000']。

Answer 1

results = {'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000'],

 'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'],

 'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'],

 'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'],

 'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003']}

score = {'agunii2035': [4, 4, 1, 3],

 'agunii3007': [4, 3, 3, 1],

 'agunii2006': [4, 3, 2, 2],

 'agunii2003': [1, 3, 2, 1],

 'agunii3000': [3, 1, 2, 1]}

ordered_results = {key:[item for _, item in

                   sorted(zip(score.get(key), value), reverse=True)]

                   for key, value in results.items()}

print(ordered_results)

输出

{'agunii2035': ['agunii3007', 'agunii2006', 'agunii3000', 'agunii2003'],

'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'],

'agunii2006': ['agunii2035', 'agunii3007', 'agunii3000', 'agunii2003'],

'agunii2003': ['agunii3007', 'agunii2006', 'agunii3000', 'agunii2035'],

'agunii3000': ['agunii2035', 'agunii2006', 'agunii3007', 'agunii2003']}

Answer 2

您需要做的就是使用从分数中查找字典的值作为对这样的结果进行排序的键。这是可行的，因为默认排序算法可以使用列表作为排序依据。key: values然后，它使用字典理解从排序列表中构建一个新字典。

results = {

    'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000'],

    'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'],

    'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'],

    'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'],

    'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003']

}

score = {

    'agunii2035': [4, 4, 1, 3],

    'agunii3007': [4, 3, 3, 1],

    'agunii2006': [4, 3, 2, 2],

    'agunii2003': [1, 3, 2, 1],

    'agunii3000': [3, 1, 2, 1]

}

sorted_results = {

    k: v

    for k, v

    in sorted(results.items(), key=lambda item: score[item[0]])

}

print(sorted_results)

# {'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'], 'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003'], 'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'], 'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'], 'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000']}