根据 String 属性对对象数组进行排序

Question

我有这样的数据结构。[         {"name": "John", "gender": "Male", "id": "1"},         {"name": "Max", "gender": "Male", "id": "2"},         {"name": "John", "gender": "Male", "id": "3"},         {"name": "Sam", "gender": "Male", "id": "4"},         {"name": "Max", "gender": "Male", "id": "5"},         {"name": "Sam", "gender": "Male", "id": "6"},         {"name": "Sam", "gender": "Male", "id": "7"},         {"name": " ", "gender": "Male", "id": "8"},         {"name": "John", "gender": "Male", "id": "9"},         {"name": " ", "gender": "Male", "id": "10"},     ]我正在尝试根据属性对其进行排序name。我需要所有记录name=max应该首先出现name=Sam，然后name=John是具有空名称字段或任何其他值的其余记录。我尝试了不同的技术，但没有得到想要的结果。有人可以建议我如何实现这一目标吗？谢谢。

Answer 1

您可以给每个name案例打分，然后在Array.sort函数中使用该分数。

const data = [

  { name: 'John', gender: 'Male', id: '1' },

  { name: 'Max', gender: 'Male', id: '2' },

  { name: 'John', gender: 'Male', id: '3' },

  { name: 'Sam', gender: 'Male', id: '4' },

  { name: 'Max', gender: 'Male', id: '5' },

  { name: 'Sam', gender: 'Male', id: '6' },

  { name: 'Sam', gender: 'Male', id: '7' },

  { name: ' ', gender: 'Male', id: '8' },

  { name: 'John', gender: 'Male', id: '9' },

  { name: ' ', gender: 'Male', id: '10' }

];

const getScore = name => {

  if (name === 'Max') return 3;

  else if (name === 'Sam') return 2;

  else if (name === 'John') return 1;

  else return 0;

};

data.sort((a, b) => getScore(b.name) - getScore(a.name));

console.log(data);

Answer 2

您可以执行以下操作，

data = [

        {"name": "John", "gender": "Male", "id": "1"},

        {"name": "Max", "gender": "Male", "id": "2"},

        {"name": "John", "gender": "Male", "id": "3"},

        {"name": "Sam", "gender": "Male", "id": "4"},

        {"name": "Max", "gender": "Male", "id": "5"},

        {"name": "Sam", "gender": "Male", "id": "6"},

        {"name": "Sam", "gender": "Male", "id": "7"},

        {"name": " ", "gender": "Male", "id": "8"},

        {"name": "John", "gender": "Male", "id": "9"},

        {"name": " ", "gender": "Male", "id": "10"},

    ]

data.sort((a, b) => {

  if(a.name < b.name) {

    return 1;

  } else if(a.name > b.name) {

    return -1;

  }

  return 0;

})

console.log(data);

Answer 3

如果您的数据包含区分大小写的名称怎么办？

const getScore = name => {

  if (name.toLowerCase() === 'max') return 3;

  else if (name.toLowerCase() === 'sam') return 2;

  else if (name.toLowerCase() === 'john') return 1;

  else return 0;

};

data.sort((a, b) => getScore(b.name) - getScore(a.name));

console.log(data);

Answer 4

您好，您可以使用此代码

var arr = [

    {"name": "John", "gender": "Male", "id": "1"},

    {"name": "Max", "gender": "Male", "id": "2"},

    {"name": "John", "gender": "Male", "id": "3"},

    {"name": "Sam", "gender": "Male", "id": "4"},

    {"name": "Max", "gender": "Male", "id": "5"},

    {"name": "Sam", "gender": "Male", "id": "6"},

    {"name": "Sam", "gender": "Male", "id": "7"},

    {"name": " ", "gender": "Male", "id": "8"},

    {"name": "John", "gender": "Male", "id": "9"},

    {"name": " ", "gender": "Male", "id": "10"},

];

var arr1 = arr.filter((value, index) => {

    if(value.name == 'Max'){

        return value

    }

});

var arr2 = arr.filter((value, index) => {

    if(value.name != 'Max'){

        return value

    }

});

arr2 = arr2.sort((a, b) => (a.name < b.name) ? 1 : -1);

var output = arr1.concat(arr2);

console.log(output);