最新回答 / darkstars
string[] name = new string[] { "景珍", "林惠洋","程蓉", "洪南昌", "龙玉明", "单江开", "田武开", "王三明" }; int[] sum = new int[] { 90, 65, 88, 70, 46, 81, 100, 68 }; Console.Write("平均分是76高于平均分的有："); for (int i = 0; i < sum.Lengt...
2020-11-16
最新回答 / darkstars
string[] name = new string[] { "景珍", "林惠洋","成蓉", "洪南昌", "龙玉明", "单江开", "田武山", "王三明" }; int[] sum = new int[] { 90, 65, 88, 70, 46, 81, 100, 68 }; Console.Write("平均分是76，高于平均分的有："); for (int i = 0; i < sum.Leng...
2020-11-04
//请完善代码，判断数组中有没有7的整倍数
bool hasSeven = false;
foreach (int temp in num) {
hasSeven = temp % 7 == 0 ? true : false ;
if(hasSeven)
break;
}
Console.Write(hasSeven ? "有7的整倍数" : "没有7的整倍数");
bool hasSeven = false;
foreach (int temp in num) {
hasSeven = temp % 7 == 0 ? true : false ;
if(hasSeven)
break;
}
Console.Write(hasSeven ? "有7的整倍数" : "没有7的整倍数");
直接改成Console.WriteLine(true);也行...系统只检查最后输出内容，不管中间过程合理不合理
2020-11-02
明白了。
1. bool a = ++x * x > 3;
bool b = a;
2. bool a = ++x * x > 3;
bool b = ++x * x > 3;
1. bool a = ++x * x > 3;
bool b = a;
2. bool a = ++x * x > 3;
bool b = ++x * x > 3;
2020-10-30
已采纳回答 / KulooM
第二张图score[i]=s的意思是把 s 的值赋给 score[i]，所以无论怎么循环，s 的值是没有变化的，一直是你开始定义的int s = score[0]，也就是第一个数，89
2020-10-26