最新回答 / 周当家的
d = { 'Alice': 45, 'Bob': 60, 'Candy': 75, 'David': 86, 'Ellena': 49}for a in d.keys(): print(a,d.get(a))打印的地方有错误 把keys换成a
2025-11-13
4个
第一个：T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))本身就是一个元组
第二个：((1+2),)
第三个：(1, )
第四个：(1,2,3,4,5)
第一个：T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))本身就是一个元组
第二个：((1+2),)
第三个：(1, )
第四个：(1,2,3,4,5)
2025-11-11
d = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66], 'Candy': [88, 75, 90]}
for key in d:
print(key)
for v in d[key]:
print(v)
print("-------------------")
for key,value in d.items():
print(key)
for vc in value:
print(vc)
for key in d:
print(key)
for v in d[key]:
print(v)
print("-------------------")
for key,value in d.items():
print(key)
for vc in value:
print(vc)
2025-10-14
d = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66], 'Candy': [88, 75, 90]}
for key in d:
print(key)
print(d[key])
print("-------------------")
for key,value in d.items():
print(key)
print(value)
for key in d:
print(key)
print(d[key])
print("-------------------")
for key,value in d.items():
print(key)
print(value)
2025-10-14
d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
print(d)
d['Alice'] = 60
print(d)
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
print(d)
d['Alice'] = 60
print(d)
2025-10-14
L = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
L.append('Gen')
L.append('Zero')
L.insert(6,'Phoebe')
for i in L:
print(i)
L.append('Gen')
L.append('Zero')
L.insert(6,'Phoebe')
for i in L:
print(i)
2025-10-12
s1 ='ABC'
s2='123'
s3='XYZ'
for a in s1:
for b in s2:
for c in s3:
print(a+b+c)
s2='123'
s3='XYZ'
for a in s1:
for b in s2:
for c in s3:
print(a+b+c)
2025-10-12
a =0
b=0
while a <= 1000:
if a % 2 != 0:
continue
b= b+a
a = a+1
print(b)
b=0
while a <= 1000:
if a % 2 != 0:
continue
b= b+a
a = a+1
print(b)
2025-10-12
a=0
sum=0
while True:
if a % 2 == 0:
sum=sum+a
a=a+1
if a > 1000:
break
print("a:{},sum:{}",a,sum)
sum=0
while True:
if a % 2 == 0:
sum=sum+a
a=a+1
if a > 1000:
break
print("a:{},sum:{}",a,sum)
2025-10-12