代码一样，怎么我的报错呢？
为啥我的一直报错data is undefined???
我都仔细对比了代码，是一样的呀！
youbaisan
2015-10-22
5 回答
var width = 500,
height = 250,
margin={left:50, top:30, right:20, bottom:20},
g_width = width - margin.left - margin.right,
g_height = height - margin.top - margin.bottom;
//svg
var svg = d3.select("#container")
.append("svg:svg")
//width, height
.attr("width", width)
.attr("height",height)
var g = d3.select("svg")
.append("g")
.attr("transform", "translate("+margin.left+", "+margin.top+")")
var data = [1,3,5,7,8,4,3,7];
var scale_x = d3.scale.linear()
.domain([0, data.length - 1])
.range([0, g_width])
var scale_y = d3.scale.linear()
.domain([0, d3.max(data)])
.range([0, g_height])
var line_generator = d3.svg.line()
.x(function(d, i){return scale_x(i);}) //0,1,2,3...
.y(function(d){ return scale_y(d);}) //1,3,5...
.interpolate("cardinal")
d3.select("g")
.append("path")
.attr("d", line_generator(data)) //d="M1,0L20,40L40,50L100,100L0,200", d - path data
var width=500,
height=250,
margin={left:50,top:30,right:20,bottom:20},
g_width = width-margin.left-margin.right,
g_height = height-margin.top-margin.bottom;
//svg
var svg = d3.select("#container")
.append("svg")
//width,height
.attr("width",width)
.attr("height",height)
var g = d3.select("svg")
.append("g")
.attr("transform","translate("+margin.left+","+margin.top+")")
var data = [1,3,6,9,2,7,3];
var scale_x = d3.scale.linear()
.domain([0,data.length-1])
.range([0,g_width])
var scale_y = d3.scale.linear()
.domain([0,d3.max(data)])
.range([0,g_height])
var line_generator = d3.svg.line()
.x(function(d,i){return scale_x(i);})//0,1,2,...
.y(function(d){return scale_y(d);})//1,2,3,...
.interpolate("cardinal")
d3.select("g")
.append("path")
.attr("d",line_generator)老师，这是我的js代码，能麻烦您看下吗？我找了好久都没找到错误！
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