我想把值打印出来看下是如何替换比较的，为啥老报错 return -1 unindent does not match any outer indentation level

class Student(object):

    def __init__(self, name, score):
        self.name = name
        self.score = score

def __str__(self):
return '(%s: %s)' % (self.name, self.score)

__repr__ = __str__

    def __cmp__(self, s):
        if self.score < s.score:
        print 'self.score:%d' %self.score

        print 's.score:%d' %s.score
            return -1
        elif self.score>s.score:
        print 'self.score:%d' %self.score
        print 's.score:%d' %s.score
        return 1
        else:

        print 'self.score:%d' %self.score
        print 's.score:%d' %s.score
        return 0
L = [Student('Tim', 99), Student('Bob', 88), Student('Alice', 100)]
print sorted(L)

慕粉1817177760

2017-01-13

源自：python进阶 6-3

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孤独的小猪
2017-01-18

代码里面，if判断里的print缩进不对，改一下缩进就正确了，如下：

# -*- coding:utf-8 -*-


class Student(object):
    def __init__(self, name, score):
        self.name = name
        self.score = score

    def __str__(self):
        return '(%s: %s)' % (self.name, self.score)
    __repr__ = __str__

    def __cmp__(self, s):
        if self.score < s.score:
            print 'self.score:%d' % self.score
            print 's.score:%d' % s.score
            return -1
        elif self.score > s.score:
            print 'self.score:%d' % self.score
            print 's.score:%d' % s.score
            return 1
        else:
            print 'self.score:%d' % self.score
            print 's.score:%d' % s.score
            return 0
L = [Student('Tim', 99), Student('Bob', 88), Student('Alice', 100)]
print sorted(L)