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这里 return cirf;为什么我删除了,还是可以正确输出,为什么?想问return 在这具体作用,它是在这为了什么?谢谢!

#include <stdio.h>
int getGirth(int a,int b,int c)
{
    if( (a+b)<=c || (a+c)<=b || (b+c)<=a )   //判断是否为三角形
    {
        printf("不构成三角形\n");
        return 0;                               
    }
    else
    {
      int cirf = a+b+c;      //计算三角形周长
   return cirf;
 }
      
}

int main()
{
    /* 定义三角形三边长 */
    int a, b, c;
    a = 3;
    b = 4;
    c = 5;
    printf("三角形的周长是:%d\n",getGirth(a,b,c));  //调用周长函数
    return 0;
}


正在回答

2 回答

return是返回值的意思 返回后面的值进入主函数  如果省略 并且函数内有形参参与运算的代数 会输出距离return最近的代数值 否则输出第一个形参

int cirf = a+b+c;

int p=a+c;

这样返回p的值 为8

int p=5;

返回a的值 为3

int p=a+c;

int cirf = a+b+c;

这样返回cirf的值 为12


0 回复 有任何疑惑可以回复我~
#1

有思需多行 提问者

非常感谢!加上程序试试,的确是
2017-12-24 回复 有任何疑惑可以回复我~

具体一点,哪里不简单了?

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这里 return cirf;为什么我删除了,还是可以正确输出,为什么?想问return 在这具体作用,它是在这为了什么?谢谢!

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