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为什么这么定义就输出不了呢，var infos=new Array[['小A','女',21,'大一'], ['小B','男',23,'大三'], ['小C','男',24,'大四'],]. 这样定义有什么错误的吗？

我們

2015-10-09

源自：JavaScript进阶篇 4-10

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3 回答

赜赜a嘚嘚
2015-10-10

var infos=new Array(['小A','女',21,'大一'], ['小B','男',23,'大三'], ['小C','男',24,'大四']) 这样写没有你那种写法吧

写法：[1]

var infos=new Array(1,2,3)

[2]

var infos=[1,2,3]

[3]

var infos=new Array()

infos[0]=1;

infos[1]=2;

infos[1]=3;

0 回复有任何疑惑可以回复我~

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我們提问者

非常感谢！谢谢

2015-10-11 回复有任何疑惑可以回复我~

楽冷风清
2015-10-15

var infos=[["小A","女","21","大一"],["小B","男","23","大三"],["小c","男","24","大四"],["小D","女","21","大一"],["小E","女","22","大四"],["小F","男","21","大一"],["小G","女","22","大二"],["小H","女","20","大三"],["小I","女","20","大一"],["小J","男","20","大三"]]; //双引号，双引号，双引号，谁说不能这样写的

//第一次筛选，找出都是大一的信息

document.write("大一的有");

for(i=0;i<infos.length;i++){

if(infos[i][3]=="大一"){

document.write(infos[i][0]+"、");

} }

//第二次筛选，找出都是女生的信息

document.write("<br/><br/>"+"女生有");

for(i=0;i<infos.length;i++){

if(infos[i][1]=="女"){

document.write(infos[i][0]+"、");

}