为啥那么总值和平均值不对

Question

#include <stdio.h>#define N 10int total(int score[]){ int i; int sum; for(i=0;i<=9;i++) { sum+=score[i]; } return sum;}int Max(int score[]){ int i; int max; //int a; for(i=0;i<=9;i++) { if(max<score[i]) { max = score[i]; } /* a=score[i+1]>score[i]?score[i+1]:score[i]; max=max>a?max:a;*/ } return max;}int Min(int score[]){ int i; int min; //int b; for(i=0;i<=9;i++) { if(min>score[i]) { min = score[i]; } /* b=score[i+1]<score[i]?score[i+1]:score[i]; min=score[i+2]<b?score[i+2]:b;*/ } return min;}float Ave(int sum){ return (sum+0.0)/N;}int main(){ int score[N]={2,11,28,10,30,6,22,8,9,10}; int sum; int i,j; int temp; sum=total(score); printf("Total score:%d\n",sum); printf("Max score:%d\n",Max(score)); printf("Min score:%d\n",Min(score)); printf("Average score:%.1f\n",Ave(sum)); puts("changed:"); for(j=1;j<N;j++) { for(i=1;i<N-j;i++) { if(score[i]>score[i+1]) { temp=score[i]; score[i]=score[i+1]; score[i+1]=temp; } } } for(i=0;i<=9;i++) { printf("%d\n",score[i]); } return 0;}

Answer 1

sum,max,min三个函数里面的三个变量都没有赋初值。

Answer 2

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Answer 3

C语言语法忘得差不多了

Answer 4

total函数的sum初值应为零

Answer 5

还有就是你这里主函数冒泡排序内层循环i的初值不应该是0吗？

Answer 6

不好意思，我也是个渣！