$files = array(            "name" => array("2374102_middle.jpg","2374102_middle.jpg"),            "type" => array("image/jpeg","image/jpeg"));转化成$filename = array( 		array("name" => "2374102_middle.jpg","type" => "image/jpeg"),                array("name" => "2374102_middle.jpg", "type" => "image/jpeg")        ); 求代码,及分析思路。。。。。。
                    
                    
                1 回答
                        已采纳
                    
                                        
                         
                    
                    
                            KevenHuang
                            
                        
                                                
                    TA贡献280条经验 获得超233个赞
                                $filename=array();
foreach($file as $key=>$val){
    foreach($val as $k=>$v){
        if($k=="name"){
            $filename[$k]["name"]=$v;
        }else{
            $filename[$k]["type"]=$v;
        }
    }
}
(纯手打代码)
                            
                            
                        - 1 回答
- 0 关注
- 1196 浏览
添加回答
举报
0/150
	提交
		取消
	