python 怎么输出下图的字符表

Answer 1

m=32
n=32
for i in range((127-32+1)//16*2):
    if i%2==0:
        print('chr:'+'\t',end='')
        for j in range(m,16+m):
            print(chr(j)+'\t',end='')
        m += 16
    if i%2==1:
        print('asc:'+'\t',end='')
        for k in range(n,16+n):
            print(str(k)+'\t',end='')
        n += 16
    print('')