DATA='[{"status": "IN_PROGRESS", "loan_limited": "5个月", "load_no": "123131231", "payed": "1个月", "amount": 15000, "loan_time": "2016-06-17"}, {"status": "DONE", "loan_limited": "1个月", "load_no": "123131123131231", "payed": "1个月", "amount": 15000, "loan_time": "2016-05-17"}, {"status": "IN_PROGRESS", "loan_limited": "5个月", "load_no": "123131231231", "payed": "1个月", "amount": 25000, "loan_time": "2016-06-10"}]';将上面数据中日期格式改为xx年xx月xx日
1 回答

MM们
TA贡献1886条经验 获得超2个赞
'2016-06-17'.replace(/(\d{4})-(\d{2})-(\d{2})/g,'$1年-$2月-$3日')"2016年-06月-17日";
套用到你的上面:
var DATA = '[{"status": "IN_PROGRESS", "loan_limited": "5个月", "load_no": "123131231", "payed": "1个月", "amount": 15000, "loan_time": "2016-06-17"}, {"status": "DONE", "loan_limited": "1个月", "load_no": "123131123131231", "payed": "1个月", "amount": 15000, "loan_time": "2016-05-17"}, {"status": "IN_PROGRESS", "loan_limited": "5个月", "load_no": "123131231231", "payed": "1个月", "amount": 25000, "loan_time": "2016-06-10"}]'; DATA=DATA.replace(/(\d{4})-(\d{2})-(\d{2})/g, '$1年-$2月-$3日'); //"[{"status": "IN_PROGRESS", "loan_limited": "5个月", "load_no": "123131231", "payed": "1个月", "amount": 15000, "loan_time": "2016年-06月-17日"}, {"status": "DONE", "loan_limited": "1个月", "load_no": "123131123131231", "payed": "1个月", "amount": 15000, "loan_time": "2016年-05月-17日"}, {"status": "IN_PROGRESS", "loan_limited": "5个月", "load_no": "123131231231", "payed": "1个月", "amount": 25000, "loan_time": "2016年-06月-10日"}]"
添加回答
举报
0/150
提交
取消