原型对象的constructor

Question

function Super(){    this.name = "this is super";}Super.prototype = {    say:function(){        console.log(this.name);    }}function Sub(){    this.name = "this is sub";}Sub.prototype = new Super();var o = new Sub();o.say(); //this is sub实例 o 的原型对象的constructor是Super，那么 this.name 应该是Super的构造函数。但是输出是 this is sub