下面的代码是我自己写的，但是，求公约数和公倍数不是很明白，有哪位大神能给讲讲。谢谢了

Question

package com.BIyuan.method;import java.util.Scanner;public class BIyuanFenHenTao { @SuppressWarnings("unused") public void FenHenTao(int a, int b, int c) { int[] arr = { a, b, c }; int temp; for (int i = 0; i < arr.length; i++) { for (int j = 0; j < arr.length - i - 1; j++) { if (arr[j] < arr[j + 1]) { temp = arr[j]; arr[j] = arr[j + 1]; arr[j + 1] = temp; } } } for (int n : arr) { System.err.println(n); } int max = 0; for (max = arr[0] * arr[1];; max++) { if (max % a == 0 && max % b == 0 && max % c == 0) { System.out.println("样例输出" + max); } break; } } public static void main(String[] args) { BIyuanFenHenTao By = new BIyuanFenHenTao(); Scanner sc = new Scanner(System.in); System.out.println("样例输入"); int a = sc.nextInt(); int b = sc.nextInt(); int c = sc.nextInt(); By.FenHenTao(a, b, c); }}

Answer 1

代码贴成这样，基本没人看的，

给别人看代码，缩进是基本的礼貌