帮忙看看下面的代码问题 看看最下面的输出结果对不对 简要说明理由

Question

publicclass Test1       {           private int _age=10;           public int Age           {               get { return _age; }               set { _age = value; }           }           public virtual void  Output1(string name)           {               name ="Test1";               Console.Write("Test1.Output1 ：Name is "+ name);           }           public virtual void Output2(ref stringrefname)           {               refname = "Test1";               Console.Write("Test1.Output2 ：Name is " + refname);           }       }       public class Test2:Test1       {           private int _age=20;           public override void Output1(stringname)           {               name ="Test2";               Console.Write("Test2.Output1 ：Name is "+ name);           }           public new void Output2(ref stringrefname)           {               refname = "Test2";               Console.Write("Test2.Output2 ：Name is " + refname);           }           }           string name = "Name";           string refname = "RefName";           Test1 t1 = new Test2();           t1.Output1(name);  //输出1？           t1.Output2(ref refname);  // 输出2？           Console.Write(name); // 输出3？           Console.Write(refname); // 输出4？           Test2 t2 = new Test2();           Console.Write(t2.Age.ToString()); //输出5以及是否装箱？           t2.Output2(ref refname);  //输出6

Answer 1

Test2类重写了Test1类的OutPut1方法，隐藏了OutPut2方法，因此t1.OutPut1(name)输出应该调用的是重写后的方法即t2中的方法，输出应为：est2.Output1 ：Name is Test2；t1.OutPut2(ref refname)输出应该是：Test1.Output2 ：Name is  Test1。Console.Write(name)输出为：Name;Console.Write(refName）应为Test2。Console.Write(t2.Age.ToString())不是很清楚。t2.Output2(ref refname)输出：Test2.Output2 ：Name is  test2