jsp类的静态属性如何显示到网页中 ?

Question

1.直接上类代码：import javax.servlet.http.*;public class listenTest implements HttpSessionListener{public static int count; --此处定义了静态变量public listenTest() {super();// TODO Auto-generated cons;tructor stubcount=0;}....2.在网页中引用的格式：<%=listenTest.count %> 3.在运行网页进行测试时的错误：An error occurred at line: 113 in the jsp file: /index.jsplistenTest cannot be resolved to a variable110: 111: <%/**涓嬮溃涓鸿〃鍗曞强鍙傛暟銆佽烦杞祴璇�/ %>112: <% out.print("--------------------------琛ㄥ崟娴嬭瘯 -----------------------------------------"); %>113: <%=listenTest.count %> 114: 115: 116: <form name="form1" action="x.ao" method="post"><br>

Answer 1

要实现JSP静态属性在网页中显示，应考虑对象和静态函数两种情况，具体如下：
1、对象。参照jsp:bean的用法，配合使用jsp:getProperty即可。
2、静态的函数。在
<%@ page language="java" import="java.util.*,com.rh.entity.*" contentType="text/html; charset=GB18030"
pageEncoding="GB18030"%>
import="java.util.*,com.rh.entity.*" 加上这句，保证Infomation 类的全路径，即可在jsp中使用
<%=Infomation.getJavaRuntimeVersion() %>
综上，JSP静态属性即可显示在网页中.