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一个多层嵌套的json数据,我想取它每一个children下面的name值,请问怎么取?而且这个json的嵌套层数还可能会增加。

一个多层嵌套的json数据,我想取它每一个children下面的name值,请问怎么取?而且这个json的嵌套层数还可能会增加。

茅侃侃 2019-05-13 11:23:41
[{"children":[],"users":null,"id":"//嘿嘿嘿","name":"嘿嘿嘿","nikeName":null,"indexPeople":null,"phone":"2232223","mailPhone":"2231113","ade":"故事的故事告诉","mailNumber":"1232333","parentId":"/"},{"children":[{"children":[],"users":null,"id":"//测试1234/测试1234565","name":"测试1234565","nikeName":null,"indexPeople":null,"phone":"3325663","mailPhone":"3326663","ade":"沙发沙发上地方","mailNumber":"325666","parentId":"//测试1234"}],"users":null,"id":"//测试1234","name":"测试1234","nikeName":null,"indexPeople":null,"phone":"3325663","mailPhone":"332552","ade":"发斯蒂芬斯蒂芬是","mailNumber":"326544","parentId":"/"},{"children":[{"children":[],"users":null,"id":"//违法监察机关/青白江执法队","name":"青白江执法队","nikeName":null,"indexPeople":null,"phone":"3325335","mailPhone":"3323663","ade":"公司公司归属感","mailNumber":"326322","parentId":"//违法监察机关"}],"users":null,"id":"//违法监察机关","name":"违法监察机关","nikeName":null,"indexPeople":null,"phone":"3325336","mailPhone":"3325336","ade":"的桑葚是的故事告诉","mailNumber":"326511","parentId":"/"}]
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江户川乱折腾

TA贡献1851条经验 获得超5个赞

写个递归方法来获取children里面name值,你最后想得到是个数组,[name1.name2,name3...],这样的格式,还是说数组里面是对象的格式呢?
                            
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反对 回复 2019-05-13
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