async await 并发执行的问题

Question

asyncsleep(i){returnnewPromise((resolve,reject)=>{setTimeout(function(){resolve(i);},1000);});}asyncstart(finsh_callback){console.time('g');for(leti=0;i

Answer 1

for(leti=0;i<5;i++){
(async()=>{letres=awaitsleep({
i:i,
});
console.log(res);})()
}
这个也可以实现,但是和Promise.all是有本质区别的