请教，如何处理下面的这种格式

Question

[{time:12/30/2018,cabin:'w',Type:'NonStop',dcp:37},{time:12/30/2018,cabin:'w',Type:'NonStop',dcp:37},{time:12/31/2018,cabin:'a',Type:'NonStop',dcp:37},{time:12/31/2018,cabin:'w',Type:'NonStop',dcp:37},{time:12/31/2018,cabin:'w',Type:'NonStop',dcp:37},{time:12/30/2017,cabin:'w',Type:'NonStop',dcp:37},{time:12/31/2017,cabin:'w',Type:'NonStop',dcp:37},{time:12/31/2017,cabin:'w',Type:'NonStop',dcp:37},{time:12/31/2017,cabin:'w',Type:'NonStop',dcp:37},{time:12/31/2017,cabin:'j',Type:'NonStop',dcp:37},][{time:12/30/2018,cabin:'w',Type:'NonStop',dcp:74,w:2},{time:12/31/2018,cabin:'w',Type:'NonStop',dcp:74,w:2},{time:12/31/2018,cabin:'a',Type:'NonStop',dcp:37,a:1},{time:12/31/2017,cabin:'w',Type:'NonStop',dcp:111,w:3},{time:12/31/2017,cabin:'j',Type:'NonStop',dcp:37,j:1},]请问各位大佬，如何把上面的数组整合成下面的数组形式啊，只要是日期相同，cabin相同，那么他们的其他字段的数值就相加,并且把cabin字段的value取出来变为一个新的字段加入当前对象，而它的值则是重复的数量，就是同一日期同一个cabin的数量

Answer 1

constresData=sourceData.reduce((prev,cur,index,src)=>{
if(!index)return[{...cur,[cur.cabin]:1}]
constprevEle=prev[prev.length-1]
if(cur.time===prevEle.time&&cur.cabin===prevEle.cabin){
prevEle[prevEle.cabin]++
prevEle.dcp+=cur.dcp
}else{
prev.push({...cur,[cur.cabin]:1})
}
returnprev
},[])
                            

Answer 2

constnewArr=arr.reduce((a,b)=>{
let{time,cabin,dcp}=b;
letindex=a.findIndex(val=>{
returnval.time===time&&val.cabin===cabin;
});
if(index>=0){
letcur=a[index];
cur[cabin]++;
cur['dcp']+=dcp;
}else{
letclone={...b};
clone[cabin]=1;
a.push(clone);
}
returna;
},[]);
时间格式被转换了，需要自行调整下