在SWIFT中将字典转换为JSON我已经创建了下一个字典:var postJSON = [ids[0]:answersArray[0], ids[1]:answersArray[1], ids[2]:answersArray[2]] as Dictionary我得到了:[2: B, 1: A, 3: C]那么,如何将其转换为JSON呢?
3 回答
POPMUISE
TA贡献1765条经验 获得超5个赞
SWIFT 3.0
NSJSONSerialization
let dic = ["2": "B", "1": "A", "3": "C"]do {
let jsonData = try JSONSerialization.data(withJSONObject: dic, options: .prettyPrinted)
// here "jsonData" is the dictionary encoded in JSON data
let decoded = try JSONSerialization.jsonObject(with: jsonData, options: [])
// here "decoded" is of type `Any`, decoded from JSON data
// you can now cast it with the right type
if let dictFromJSON = decoded as? [String:String] {
// use dictFromJSON }} catch {
print(error.localizedDescription)}SWIFT 2.x
do {
let jsonData = try NSJSONSerialization.dataWithJSONObject(dic, options: NSJSONWritingOptions.PrettyPrinted)
// here "jsonData" is the dictionary encoded in JSON data
let decoded = try NSJSONSerialization.JSONObjectWithData(jsonData, options: [])
// here "decoded" is of type `AnyObject`, decoded from JSON data
// you can now cast it with the right type
if let dictFromJSON = decoded as? [String:String] {
// use dictFromJSON }} catch let error as NSError {
print(error)}SWIFT 1
var error: NSError?if let jsonData = NSJSONSerialization.dataWithJSONObject(dic, options: NSJSONWritingOptions.PrettyPrinted, error: &error) {
if error != nil {
println(error)
} else {
// here "jsonData" is the dictionary encoded in JSON data }}if let decoded = NSJSONSerialization.JSONObjectWithData(jsonData, options: nil, error: &error) as? [String:String] {
if error != nil {
println(error)
} else {
// here "decoded" is the dictionary decoded from JSON data }}
海绵宝宝撒
TA贡献1809条经验 获得超8个赞
let dict = ["0": "ArrayObjectOne", "1": "ArrayObjecttwo", "2": "ArrayObjectThree"]var error : NSError?let jsonData = try! NSJSONSerialization.dataWithJSONObject(dict, options: NSJSONWritingOptions.PrettyPrinted)let jsonString = NSString(data: jsonData, encoding: NSUTF8StringEncoding)! as Stringprint(jsonString)
{
"0" : "ArrayObjectOne",
"1" : "ArrayObjecttwo",
"2" : "ArrayObjectThree"}- 3 回答
- 0 关注
- 1342 浏览
添加回答
举报
0/150
提交
取消
