XSLT是否具有Split（）函数？

Question

我在节点中有一个字符串，我想将字符串拆分为'？' 并返回数组中的最后一项。例如，在下面的块中：<a>    <xsl:attribute name="href">        /newpage.aspx?<xsl:value-of select="someNode"/>    </xsl:attribute>    Link text</a>我想分割someNode价值。编辑：这是我用来为我的Asp.Net页面加载Xsl的VB.Net：Dim xslDocPath As String = HttpContext.Current.Server.MapPath("~/App_Data/someXslt.xsl")Dim myXsltSettings As New XsltSettings()Dim myXMLResolver As New XmlUrlResolver()myXsltSettings.EnableScript = TruemyXsltSettings.EnableDocumentFunction = TruemyXslDoc = New XslCompiledTransform(False)myXslDoc.Load(xslDocPath, myXsltSettings, myXMLResolver)Dim myStringBuilder As New StringBuilder()Dim myXmlWriter As XmlWriter = NothingDim myXmlWriterSettings As New XmlWriterSettings()myXmlWriterSettings.ConformanceLevel = ConformanceLevel.AutomyXmlWriterSettings.Indent = TruemyXmlWriterSettings.OmitXmlDeclaration = TruemyXmlWriter = XmlWriter.Create(myStringBuilder, myXmlWriterSettings)myXslDoc.Transform(xmlDoc, argumentList, myXmlWriter)Return myStringBuilder.ToString()

Answer 1

使用递归方法：

<xsl:template name="output-tokens">

    <xsl:param name="list" /> 

    <xsl:variable name="newlist" select="concat(normalize-space($list), ' ')" /> 

    <xsl:variable name="first" select="substring-before($newlist, ' ')" /> 

    <xsl:variable name="remaining" select="substring-after($newlist, ' ')" /> 

    <id>

        <xsl:value-of select="$first" /> 

    </id>

    <xsl:if test="$remaining">

        <xsl:call-template name="output-tokens">

            <xsl:with-param name="list" select="$remaining" /> 

        </xsl:call-template>

    </xsl:if>

</xsl:template>

Answer 2

我最终使用了这个substring-after()功能。这对我有用：

<a>

    <xsl:attribute name="href">

        /newpage.aspx?<xsl:value-of select="substring-after(someNode, '?')"/>

    </xsl:attribute>

    Link text

</a>

即使将我的XSLT版本设置为2.0，我仍然'tokenize()' is an unknown XSLT function.在尝试使用时出现“ ”错误tokenize()。