删除括号之间的文本PHP

Question

我只是想知道如何在php中删除一组括号和括号本身之间的文本。范例：ABC（测试1）我想删除（Test1），只离开ABC谢谢

Answer 1

$string = "ABC (Test1)";

echo preg_replace("/\([^)]+\)/","",$string); // 'ABC '

preg_replace是基于Perl的正则表达式替换例程。该脚本的作用是匹配所有出现的右括号，后跟任意数量的字符而不是右括号，然后再次跟右括号，然后将其删除：

正则表达式细分：

/  - opening delimiter (necessary for regular expressions, can be any character that doesn't appear in the regular expression

\( - Match an opening parenthesis

[^)]+ - Match 1 or more character that is not a closing parenthesis

\) - Match a closing parenthesis

/  - Closing delimiter

Answer 2

$string = "ABC (Test1(even deeper) yes (this (works) too)) outside (((ins)id)e)";

$paren_num = 0;

$new_string = '';

foreach($string as $char) {

    if ($char == '(') $paren_num++;

    else if ($char == ')') $paren_num--;

    else if ($paren_num == 0) $new_string .= $char;

}

$new_string = trim($new_string);

它通过遍历每个字符并计算括号来工作。仅当$paren_num == 0（在所有括号之外）时，才将字符附加到结果字符串中$new_string。