如何在JSONObject中修改单个值？

Question

我正在使用Google Play游戏快照，并且必须使用JSON传递需要保存的数据。这是JSON文件：{"Date":1531043635316,"Daily bonus":2,"sound enabled":true,"total coins":2099300,"high score":0,"Btns Set":1,"leftBtnX":46,"leftBtnY":18,"leftBtnsize":1,"upBtnX":105,"upBtnY":18,"upBtnsize":1,"rightBtnX":164,"rightBtnY":18,"rightBtnsize":1,"guardBtnX":288,"guardBtnY":18,"guardBtnsize":1,"chargeBtnX":363,"chargeBtnY":18,"chargeBtnsize":1,"attackBtnX":438,"attackBtnY":18,"attackBtnsize":1,"superBtnX":438,"superBtnY":58,"superBtnsize":1,"ultimateBtnX":363,"ultimateBtnY":58,"ultimateBtnsize":1,"dpadX":80,"dpadY":40,"dpadSize":1,"gpadX":405,"gpadY":59,"gpadSize":1}现在，当我尝试使用此代码仅更改其中之一时：private byte[] saveToJSON(){    try {        JSONObject obj = new JSONObject();        obj.put("total coins", Settings.totalCoins);        return obj.toString().getBytes();    } catch (JSONException e) {        e.printStackTrace();        throw new RuntimeException("Error converting save data to JSON.", e);    }}整个文件的get更改为仅此单个参数，它变为：{"total coins":2099300}现在如何只修改一个参数值？抱歉，这是我第一次使用JSON