Python - 将列表变成卷轴

Question

抱歉没有正确解释。reel = ["c", "a", "c", "c", "a", "c", "d", "d", "b", "b", "b", "b", "a", "b"]outcome = ["A","A",0,0,0,0,0,0,"A","A"]x = randint(0, len(reel1)-1)假设 x= len(reel1)-2。我们希望通过 reel[len(reel1)-2]、reel[len(reel1)-1]、reel[0] 等来感受“结果”中的所有 0。只是 x 中 0 的数量会有所不同，我需要一个通用方法。

Answer 1

我想我明白你在这里想做什么；

说卷轴 = [0,1,2,3,4,5,6,7] 你想得到结果 = [6,7,0,1,2,3,4,5]

这行得通吗？

from random import randint

reel = [0,1,2,3,4,5,6,7]

start = randint(min(reel),max(reel))

outcome = reel[start:]

outcome.extend(reel[:start])