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使用 multiprocess.Pool 同时运行 2 个瓶子应用程序

使用 multiprocess.Pool 同时运行 2 个瓶子应用程序

精慕HU 2021-09-14 17:23:41
我遇到了需要同时运行 2 个应用程序(在不同端口上)的情况。我知道这可能不是最好的想法/设计,但请耐心等待。主要问题bottle.run是阻塞。显而易见的解决方法是使用multiprocessing.Pool,但我想这不是那么明显。这有效(在 2 个不同的端口上运行相同的应用程序):from multiprocessing import Poolimport bottleapp = bottle.Bottle()@app.route('/')def index():    return 'hi'def run_app(port):    bottle.run(port=port)if __name__ == '__main__':    pool = Pool(2)    ps = [pool.apply_async(run_app, (port,))          for port in (8081, 8082)]    [p.get() for p in ps]  # YES, using a list comp for side-effect输出是Bottle v0.12.15 server starting up (using WSGIRefServer())...Listening on http://127.0.0.1:8081/Hit Ctrl-C to quit.Bottle v0.12.15 server starting up (using WSGIRefServer())...Listening on http://127.0.0.1:8082/Hit Ctrl-C to quit.但是,尝试使用 2 个不同的应用程序是行不通的。from multiprocessing import Poolimport bottleapp1 = bottle.Bottle()app2 = bottle.Bottle()apps = [app1, app2]@app1.route('/')def index_app1():    return 'app1'@app2.route('/')def index_app2():    return 'app2'def run_app(app, port):    bottle.run(app, port=port)if __name__ == '__main__':    pool = Pool(2)    ps = [pool.apply_async(run_app, (app, port))          for app, port in zip(apps, [8081, 8082])]    [p.get() for p in ps]这输出Traceback (most recent call last):  File "test.py", line 29, in <module>    [p.get() for p in ps]  File "test.py", line 29, in <listcomp>    [p.get() for p in ps]  File "D:\Python37\Lib\multiprocessing\pool.py", line 657, in get    raise self._value  File "D:\Python37\Lib\multiprocessing\pool.py", line 431, in _handle_tasks    put(task)  File "D:\Python37\Lib\multiprocessing\connection.py", line 206, in send    self._send_bytes(_ForkingPickler.dumps(obj))  File "D:\Python37\Lib\multiprocessing\reduction.py", line 51, in dumps    cls(buf, protocol).dump(obj)AttributeError: Can't pickle local object 'ConfigDict.__init__.<locals>.<lambda>'更新将第一个示例更改为:...def run_app(app, port):    # instead of bottle.run(port=port) which uses default_app()    app.run(port=port) # or bottle.run(app=app, port=port)...也导致同样的错误
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