如何将 try 和 catch 合并到此数组列表中？

Question

当我输入正整数以外的任何用户输入时，它会崩溃。我尝试在 Scanner 之前加入 try 和 catch，但是 for 循环的 max_players 和输入有一个红色下划线。import java.util.*;public class NameInput {public static void main(String [] args) {    ArrayList<String> players = new ArrayList<String>();    System.out.println("How many players are going to play the game?");    Scanner input = new Scanner(System.in);    int max_players = input.nextInt();    for(int i = 1; i <= max_players; i++) {        System.out.println("\nPlayer " + i + ", please state your name: ");        String name =input.next();        players.add(name);    }    System.out.println(players.size());    System.out.println(players);  }}更新：为什么在我给用户命名后问题会重新出现？import java.util.*;public class NameInput {public static void main(String [] args) {ArrayList<String> players = new ArrayList<String>();int max_players = 0;Scanner input = new Scanner(System.in);while (true) {    System.out.println("How many players are going to play the game?");    try {        max_players = input.nextInt();    } catch (InputMismatchException ee) {        System.out.println("try again");        input.nextLine ();    }    for(int i = 1; i <= max_players; i++) {        System.out.println("\nPlayer " + i + ", please state your name: ");        String name =input.next();        players.add(name);    } } } }

Answer 1

这可以使用循环并捕获异常来完成

int max_players = 0;

Scanner input = new Scanner(System.in);

while (true) {

    System.out.println("How many players are going to play the game?");

    try {

        max_players = input.nextInt();

        break;

    } catch (InputMismatchException ee) {

        System.out.println("try again");

        input.nextLine ();

    }

}

Answer 2

我尝试在 Scanner 之前加入 try 和 catch，但是 for 循环的 max_players 和输入有一个红色下划线。

要解决此问题，您需要在 try-catch 块之外声明 max_players，并为其初始化默认值。