为了账号安全,请及时绑定邮箱和手机立即绑定

无法读取 JSON:无法构造`java.util.LinkedHashMap` 的实例

无法读取 JSON:无法构造`java.util.LinkedHashMap` 的实例

千万里不及你 2021-12-30 15:48:51
如果我得到了不确定的行 JSON 数据。我应该如何设置我的班级?这是我现在的班级public class ChatMessage {private Map<String, String> message = new HashMap<>();@JsonAnyGetterpublic Map<String, String> any(){    return this.message;}public Map<String, String> getMessage() {    return this.message;}@JsonAnySetterpublic void setMessage(String key, String value) {    message.put(key, value);}@Overridepublic String toString() {    return "Message [message=" + message + "]";}}这是我从 js 发送的 json{"type":"message","user":"james","to":"","message":"Hi every"}我现在有错误org.springframework.messaging.converter.MessageConversionException: Could not read JSON: Cannot construct instance of `java.util.LinkedHashMap` (although at least one Creator exists): no String-argument constructor/factory method to deserialize from String value ('Welcome james join the room')at [Source: (byte[])" . {"type":"message","user":"james","to":"","message":"Welcome james join the room"}"; line: 1, column: 52] (through reference chain: chat.model.ChatMessage["message"]); nested exception is         com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot construct         instance of `java.util.LinkedHashMap` (although at least one Creator exists): no String-argument constructor/factory method to deserialize from String value ('Welcome james join the room')at [Source: (byte[])" . {"type":"message","user":"james","to":"","message":"Welcome james join the room"}"; line: 1, column: 52] (through reference chain: chat.model.ChatMessage["message"])因为我的 json 会像{"type":"message", "user":"james", "to":"", "message":"Welcome james join the room", "xxx":"xxxxxxxxxxxxx"}或者{"type":"message", "user":"james", "to":"", "message":"Welcome james join the room", "yyy":"xxxxxxxxxxxxx"}我应该如何设置我的班级?谢谢
查看完整描述

1 回答

?
jeck猫

TA贡献1909条经验 获得超7个赞

重命名messagejson 中的字段或messagePOJO 中的字段。根据您的 POJO 结构,jackson 试图反序列化"message":"Hi every"到您的 POJO 中的消息字段,并且无法从中创建 Map(因为它只是一个字符串)。


您的代码将使用以下 json:


{"type":"message","user":"james","to":"","json-message":"Hi every"}

或者


以下POJO:


public class ChatMessage {


private Map<String, String> map = new HashMap<>();


@JsonAnyGetter

public Map<String, String> any(){

    return this.map;

}


public Map<String, String> getMap() {

    return this.map;

}


@JsonAnySetter

public void setMap(String key, String value) {

    map.put(key, value);

}


@Override

public String toString() {

    return "Map [map=" + map + "]";

}

}


查看完整回答
反对 回复 2021-12-30
  • 1 回答
  • 0 关注
  • 4971 浏览

添加回答

举报

0/150
提交
取消
微信客服

购课补贴
联系客服咨询优惠详情

帮助反馈 APP下载

慕课网APP
您的移动学习伙伴

公众号

扫描二维码
关注慕课网微信公众号