Jest - 断言异步函数抛出测试失败

Question

得到以下失败的测试用例，我不知道为什么：foo.jsasync function throws() {  throw 'error';}async function foo() {  try {    await throws();  } catch(e) {    console.error(e);    throw e;  }}测试.jsconst foo = require('./foo');describe('foo', () => {  it('should log and rethrow', async () => {    await expect(foo()).rejects.toThrow();  });});我希望 foo 抛出但由于某种原因它只是解决并且测试失败：FAILED foo › should log and rethrow - Received function did not throw可能缺少异步等待抛出行为的一些基本细节。

Answer 1

我认为你需要的是检查被拒绝的错误

const foo = require('./foo');

describe('foo', () => {

  it('should log and rethrow', async () => {

    await expect(foo()).rejects.toEqual('error');

  });

});

Answer 2

似乎这是一个已知的错误：https : //github.com/facebook/jest/issues/1700

这虽然有效：

describe('foo', () => {

  it('should log and rethrow', async () => {

    await expect(foo()).rejects.toEqual('error')

  });

});

Answer 3

当我不想使用toEqualor toBe（如其他正确答案）时，我会使用此代码。相反，我使用toBeTruthy.

async foo() {

  throw "String error";

}

describe('foo', () => {

  it('should throw a statement', async () => {

    await expect(foo()).rejects.toBeTruthy();

  });

});