根据模式排列 PHP 数组

Question

鉴于闲置的 $array：Array ([0] => Array    (        [location_id_keep] => 25        [location_id_delete] => 1    )[1] => Array    (        [location_id_keep] => 26        [location_id_delete] => Array            (                [0] => 3                [1] => 4            )    ))我想将像休闲模式这样的元素分组到结果：Array ([0] => Array    (        [location_id_keep] => 25        [location_id_delete] => 1    )[1] => Array    (        [location_id_keep] => 26        [location_id_delete] => 3    )[2] => Array    (        [location_id_keep] => 26        [location_id_delete] => 4    ))规则应该是这样的，对于输入数组中的每个数组，将 [location_id_keep] 与每个 [location_id_delete] 分组，从而为每个 [location_id_delete] 生成一个新数组，就像在所需的输出示例中一样。到目前为止我尝试过的：foreach ($array as $id) {//check if location_id_delete have more than 1 value                if( $id["location_id_delete"][1]) {                    foreach($id["location_id_delete"] as $del){                         $array["location_id_delete"][] = $del;                    $array["location_id_keep"]=id["location_id_keep"];                    }                }            }

Answer 1

$output = array();

foreach ($array as $i => $id) {

//check if location_id_delete have more than 1 value

  if( is_array($id["location_id_delete"])) {

    foreach($id["location_id_delete"] as $del){

      $output[] = array(

        'location_id_keep' => $array[$i]["location_id_keep"],

        'location_id_delete' => $del

      );

    }

  }else{

    $output[] = $array[$i];

  }

}

var_dump($output);