我有这样的对象 var RecuiterInfo = {} RecruiterInfo.Quote: "1" RecruiterInfo.CompanyName: "Imperial Innovations", RecruiterInfo.OrganizationSize: "2", RecruiterInfo.Person.CitizanZenship: null, RecruiterInfo.Person.DOB: "Farkhonda@hotmail.com", RecruiterInfo.Person.Email: "Farkhonda", RecruiterInfo.Person.FirstName: "FaiZi", RecruiterInfo.Person.Gender: "4456565656" RecruiterInfo.Person.LastName: "4456565656", RecruiterInfo.Person.PhoneNo: "4456565656", RecruiterInfo.Person.UserId.UserName: "MTIzNDU2", RecruiterInfo.Person.UserId.Password: null我想将此对象转换为这种特定格式 { "QueryObjectID":"RecruiterInfo", "Values": [ { "AppFieldID": "Person", "Value": [ { "AppFieldID": "CitizanZenship", "Value": "1" }, { "AppFieldID": "DOB", "Value": "01/01/2019" }, { "AppFieldID": "Email", "Value": "test1@test.com" }, { "AppFieldID": "FirstName", "Value": "test" }, { "AppFieldID": "Gender", "Value": "1" }, { "AppFieldID": "LastName", "Value": "test last" }, { "AppFieldID": "PhoneNo", "Value": "7897897895" }, { "AppFieldID": "UserId", "Value": [ { "AppFieldID": "UserName", "Value": "test1@test.com" }, { "AppFieldID": "Password", "Value": "123456" } ] } ] },但它应该是通用/动态的（我不想要任何静态的东西，因为在功能中会有多个点/或嵌套对象）我认为循环将基于.（点），它会嵌套不确定谁能帮我这个json转换
2 回答
Qyouu
TA贡献1786条经验 获得超11个赞
您可以递归地执行此操作。
const convert = (obj) => {
if (obj === null) return null
if (typeof obj !== 'object') return obj
return Object.entries(obj)
.reduce((acc, [key, value]) => acc.concat({
AppFieldId: key,
Value: convert(value), // Recursive call
}), [])
}
console.log(JSON.stringify(convert(RecruiterInfo), null, 2))
这并不完全像你想要的那样，但你首先需要静态的东西。
[
{
"AppFieldId": "Quote",
"Value": "1"
},
{
"AppFieldId": "CompanyName",
"Value": "Imperial Innovations"
},
{
"AppFieldId": "OrganizationSize",
"Value": "2"
},
{
"AppFieldId": "Person",
"Value": [
{
"AppFieldId": "CitizanZenship",
"Value": null
},
{
"AppFieldId": "DOB",
"Value": "Farkhonda@hotmail.com"
},
{
"AppFieldId": "Email",
"Value": "Farkhonda"
},
{
"AppFieldId": "FirstName",
"Value": "FaiZi"
},
{
"AppFieldId": "Gender",
"Value": "4456565656"
},
{
"AppFieldId": "LastName",
"Value": "4456565656"
},
{
"AppFieldId": "PhoneNo",
"Value": "4456565656"
},
{
"AppFieldId": "UserId",
"Value": [
{
"AppFieldId": "UserName",
"Value": "MTIzNDU2"
},
{
"AppFieldId": "Password",
"Value": null
}
]
}
]
}
]
幕布斯7119047
TA贡献1794条经验 获得超8个赞
您可以采用迭代方法。
var data = { 'RecruiterInfo.Quote': "1", 'RecruiterInfo.CompanyName': "Imperial Innovations", 'RecruiterInfo.OrganizationSize': "2", 'RecruiterInfo.Person.CitizanZenship': null, 'RecruiterInfo.Person.DOB': "Farkhonda@hotmail.com", 'RecruiterInfo.Person.Email': "Farkhonda", 'RecruiterInfo.Person.FirstName': "FaiZi", 'RecruiterInfo.Person.Gender': "4456565656", 'RecruiterInfo.Person.LastName': "4456565656", 'RecruiterInfo.Person.PhoneNo': "4456565656", 'RecruiterInfo.Person.UserId.UserName': "MTIzNDU2", 'RecruiterInfo.Person.UserId.Password': null },
result = Object.entries(data).reduce((r, [s, v]) => {
var path = s.split('.'),
last = path.pop();
path
.reduce((o, k, i) => {
var temp = o.find(q => q[i ? 'AppFieldID' : 'QueryObjectID'] === k);
if (!temp) o.push(temp = i ? { AppFieldID: k, Value: [] } : { QueryObjectID: k, Values: [] });
return temp[i ? 'Value' : 'Values'];
}, r)
.push({ AppFieldID: last, Value: v });
return r;
}, []);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
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