遍历字典中的列表

Question

我有一本看起来像这样的字典：{   "month": ["January", "February", "March"],   "volume": [1,2,3],   "target": [6,8,5]}我想遍历每个键和值，以便我可以制作一个如下所示的列表：["month: January, volume: 1, target: 6", "month: February, volume: 2, target: 8", "month: March, volume: 3, target: 5"]如何逐个循环遍历每个键值，直到到达最后一个列表的数组值的末尾？对于每个键，所有列表的长度相同。

Answer 1

d = {

   "month": ["January", "February", "March"],

   "volume": [1,2,3],

   "target": [6,8,5]

}

keys = tuple(d)  # ('month', 'volume', 'target')

values = tuple(zip(*d.values()))  # (('January', 1, 6), ('February', 2, 8), ('March', 3, 5))

your_list = [

    ', '.join(

        f'{keys[i]}: {value[i]}' 

        for i in range(len(keys))  # range(3) in this case

    ) 

    for value in values

]

print(your_list)

输出：

['month: January, volume: 1, target: 6',

 'month: February, volume: 2, target: 8',

 'month: March, volume: 3, target: 5']

Answer 2

使用这个例子：

di = {

   "month": ["January", "February", "March"],

   "volume": [1,2,3],

   "target": [6,8,5],

}

一个想法是将其转换为列表

li = [ [k + ": " +str(v) for v in v_list] for k,v_list in test_dict.items()]

然后使用 zip 进行连接

[ ', '.join(l) for l in zip(*li) ]

这是结果：

['month: January, volume: 1, target: 6',

 'month: February, volume: 2, target: 8',

 'month: March, volume: 3, target: 5']

Answer 3

假设所有值具有相同的长度：

di = {

    "month": ["January", "February", "March"],

    "volume": [1,2,3],

    "target": [6,8,5],

}

sample_length = len(list(di.values())[0])

final_list = []

for j in range(sample_length):

    list_item = []

    for key, val in di.items():

        list_item.append('{}: {}'.format(key, val[j]))

    final_list.append(', '.join(list_item))

print(final_list)

输出：

['month: January, volume: 1, target: 6', 'month: February, volume: 2, target: 8', 'month: March, volume: 3, target: 5']