将值发送到另一个函数 golang

Question

我做了一个有 4 个房间的随机房间程序。我正在尝试获取每个房间的属性并将它们传递给其他功能。每个房间里都有一个人，有一个名字和一个年龄属性。我正在尝试传递这些属性来测试 if 语句以发出额外的响应。如何传递这些值？//the random maze room gamepackage main//All imports can be combined into ()import ("fmt"        //Import needed for random operation        "math/rand"        //Import requied to call upon current time         "time")type Person struct {    Name string    Age int}func main(){    // These two lines are designed to reset the random Seed every time the program is run     // Unless the randomizer is seeded, Golang 1.6 is pseudo-random,     // always defaulting to Seed(1)     s1 := rand.NewSource(time.Now().UnixNano())    r1 := rand.New(s1)    switch r1.Intn(4){    case 0:        westRoom()    case 1:        eastRoom()    case 2:        northRoom()    case 3:        southRoom()    default:        lostRoom()    }    p := Person{}    p.Name = Avatarname    p.Age = Avatarage    avatar(&p)    appearance(&p)  }func westRoom(){    fmt.Println("You find yourself in a room with three walls, and a door behind you.")    fmt.Println("The opposite wall is a window, overlooking the sea")    Avatarname := "Bill"    Avatarage := 25    return}func eastRoom(){    fmt.Println("You find yourself in a room with a door on the walls to your left, right, and behind you")    fmt.Println("on the wall across from you is a painting of a mountain scene")    Avatarname := "Mary"    Avatarage := 33    return}func northRoom(){    fmt.Println("You find yourself in a room with a door on the wall behind you")    fmt.Println("You see several statues of people standing around the room")    Avatarname := "Joe"    Avatarage := 58    return}func southRoom(){    fmt.Println("You find yourself in a room with a door on the wall in front and behind you")    Avatarname := "Abagail"    Avatarage := 67    return}func lostRoom(){    fmt.Println("You are unable to find a room in a maze filled only with rooms")    fmt.Println("It's almost like the programmer didn't know what he was doing")}

Answer 1

一种方法是更改房间函数以返回Person结构或结构的属性Person。

在此处查看实时代码：The Go Playground

例如，

func northRoom() *Person{

  fmt.Println("You find yourself in a room with a door on the wall behind you")

  fmt.Println("You see several statues of people standing around the room")

  return &Person{"Joe", 58}

}

switch现在，您的语句中的函数调用可以期望Person返回一个结构。

var p *Person

switch r1.Intn(4){

case 0:

    p = westRoom()

case 1:

    p = eastRoom()

case 2:

    p = northRoom()

case 3:

    p = southRoom()

default:

    p = lostRoom()

}

avatar(p)

appearance(p) 

请注意，您需要更改avatar()和appearance()函数的签名以接受*Person参数。

Answer 2

为什么不让您的房间功能返回 a Person？例子：

func main() {

    // These two lines are designed to reset the random Seed every time the program is run

    // Unless the randomizer is seeded, Golang 1.6 is pseudo-random,

    // always defaulting to Seed(1)

    s1 := rand.NewSource(time.Now().UnixNano())

    r1 := rand.New(s1)

    var p Person

    switch r1.Intn(4) {

    case 0:

        p = westRoom()

    case 1:

        p = eastRoom()

    case 2:

        p = northRoom()

    case 3:

        p = southRoom()

    default:

        lostRoom()

    }

    p.printAvatar()

    p.printAppeareance()

}

func westRoom() Person {

    fmt.Println("You find yourself in a room with three walls, and a door behind you.")

    fmt.Println("The opposite wall is a window, overlooking the sea")

    return Person{

        Name: "Bill",

        Age:  25,

    }

}

https://play.golang.org/p/9_PuPsRdXg