3 回答

TA贡献1854条经验 获得超8个赞
这是一种方法:
import random
num1 = random.randint(-5, 4)
num2 = random.randint(-5, 4)
counter = 1
while num1 * num2:
#while will iterate until the condition is not true, in python 0 is equivalent to false.
num1 = random.randint(-5, 4)
num2 = random.randint(-5, 4)
counter += 1
print("Took this many iterations: ", counter)
没有初始化的例子num1和num2
import random
counter = 1
while random.randint(-5, 4) * random.randint(-5, 4):
counter += 1
print("Took this many iterations: ", counter)

TA贡献1874条经验 获得超12个赞
您生成一对数字,并使用该产品来运行您的循环。由于产品无法更改,因此它是一个无限循环。尝试这个:
import random
product = 10000 # Dummy value to get into the loop.
while product != 0:
num1 = random.randint(-5, 4)
num2 = random.randint(-5, 4)
print("Generated number 1: ", num1)
print("Generated number 2: ", num2)
product = num1 * num2
print("Product result: ", product)
if product != 0:
print("Failed iteration")
else:
print("Successful iteration")

TA贡献1772条经验 获得超8个赞
random.randint(a, b)返回一个随机整数N,这样a <= N <= b
random.randrange(a, b)返回一个随机整数N,这样注意和a <= N < b
之间的区别<<=
如果您想要 -5 到 5(含)范围内的数字,那么您 需要
randint(-5, 5)
...
randrange(-5, 6)
randint(-5, 4)
以下代码将实现您的目标:
import random
iteration_number = 0
while True:
iteration_number += 1
num1 = random.randint(-5, 5)
num2 = random.randint(-5, 5)
print("Generated number 1: ", num1)
print("Generated number 2: ", num2)
product = num1 * num2
print("Product result: ", product)
if product == 0:
break # exit the loop
print("We iterated", iteration_number, "times.")
虽然上面的代码有效,但它相当难看。这是因为它曾经是一个庞大的脚本,而不是分解成单独的函数。下面的代码实现了相同的最终结果,但更易于阅读、理解和修改:
import random
def gen_once():
"""
generate data once
"""
num1 = random.randint(-5, 5)
num2 = random.randint(-5, 5)
return num1, num2
def test_once(num1, num2):
if num1 * num2 == 0:
return True
return False
def gen_and_test_once():
num1, num2 = gen_once()
return test_once(num1, num2)
def gen_and_test_many():
iteration_number = 0
while True:
iteration_number += 1
test_result = gen_and_test_once()
if product == 0:
return iteration_number
iteration_count = gen_and_test_many()
print("We iterated", iteration_count, "times.")
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