jq的next()函数时，为什么显示thisObj.next is not a function？

Question

-----HTML----<img class="my-img" id="myimg" src="images/resources.png" onmouseout="hidebutton(this)"onmouseover="showbutton(this)"><div id="button" class="button"><button>隐藏按钮</button></div>----------jq--------function hidebutton(thisObj) {debugger;thisObj.next(".button").css("display", "none");}

Answer 1

thisObj这个是DOM元素
$(thisObj).next 就对了