主函数有了，求C语言编写函数求数组中最小值？怎么实现？

Question

int main(){int array[MAX_SIZE], size, index;scanf("%d", &size);get_array(array, size);index = min_index(array, size);printf("minimum number is %d, whose position is %d.", array[index], index);return 0;}

Answer 1

int min=array[0];for(int i=1;i<size;i++){    if(min>a[i])        {            min=a[i];            index=i;        }}return min;

Answer 2

#include <stdio.h>
#define MAX_SIZE 100 //我随便写的，需要自己改
void get_array(int *array,int size)
{
printf("请输入：\n");
for(int i=0;i<size;i++)
scanf("%d",&array[i]);
}
int min_index(int *array,int size)
{
int min=array[0];
for(int i=1;i<size;i++)
if(array[i]<min)
min=array[i];
return min;
}
int main()
{
int array[MAX_SIZE], size, index;

scanf("%d", &size);
get_array(array, size);//上面已经给出函数
index = min_index(array, size);//在main函数前不用声明
printf("minimum number is %d, whose position is %d.\n", array[index], index);

return 0;
}

Answer 3

#include"stdio.h"

#define MAX_SIZE 100

void get_array(int a[],int size)

{int i;

 for(i=0;i<size;i++)

scanf("%d",&a[i]);

}

int min_index(int a[],int size)

{int i,min=0;

 for(i=1;i<size;i++)

if(a[i]<a[min])min=i;

 return min;

}

int main()

{

    int array[MAX_SIZE], size, index;

    scanf("%d", &size);

    get_array(array, size);

    index = min_index(array, size);

    printf("minimum number is %d, whose position is %d.", array[index], index);

system("pause");

    return 0;

}