python如何解析指定div标签中的标签

Question

我已经尝试了这个网站上的其他解决方案，但仍然无法解决问题，我的问题是：<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt我想解析这个“ds”类中的所有 div 标题，谢谢你的帮助

Answer 1

使用BeautifulSoup,lxml或类似模块代替regex.

美丽汤：

from bs4 import BeautifulSoup

text = '<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt'

soup = BeautifulSoup(text, 'html.parser')

for item in soup.select('.ds div[title]'):

    print(item['title'])

# or as list comprehensions    

titles = [item['title'] for item in soup.select('.ds div[title]')]

print(titles)

lxml：

import lxml.html

text = '<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt'

soup = lxml.html.fromstring(text)

for item in soup.cssselect('.ds div[title]'):

    print(item.attrib['title'])

# or as list comprehensions    

titles = [item.attrib['title'] for item in soup.cssselect('.ds div[title]')]

print(titles)

查询：

import pyquery

text = '<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt'

soup = pyquery.PyQuery(text)

for item in soup('.ds div[title]'):

    print(item.attrib['title'])

# or as list comprehensions    

titles = [item.attrib['title'] for item in soup('.ds div[title]')]

print(titles)

parsel : (由Scrapy 的 Selectors使用)

import parsel

sel = parsel.Selector(text)

for item in sel.css('.ds div[title]'):

    print(item.attrib['title'])

titles = [item.attrib['title'] for item in sel.css('.ds div[title]')]

print(titles)