2 回答
TA贡献1809条经验 获得超8个赞
使用pyminio来做到这一点:
from pyminio import Pyminio
pyminio_client = Pyminio.from_credentials(
endpoint='<your-minio-endpoint>', # e.g. "localhost:9000/"
access_key='<your-minio-access-key>',
secret_key='<your-minio-secret-key>'
)
pyminio_client.rm('/test/sampletest', recursive=True)
TA贡献1859条经验 获得超6个赞
要删除 minio 中的整个文件夹,您只需删除要删除的文件夹的所有内容。
在您的情况下,运行时将删除“路径”文件夹
minioClient.remove_object('test','path/p1.jpg')
minioClient.remove_object('test','path/scene1.jpg')
要以更好的方式做到这一点,您可以使用带有前缀和递归参数的 list_objects,如下所示:
from minio import Minio
from minio.error import ResponseError
minioClient = Minio('localhost:9000',
access_key='your-key',
secret_key='your-key', secure=False)
def deleteFolder2(bucketname, folderName):
# Delete using "remove_object"
objects_to_delete = minioClient.list_objects(bucketname, prefix=folderName, recursive=True)
for obj in objects_to_delete:
minioClient.remove_object(bucketname, obj.object_name)
def deleteFolder1(bucketname, folderName):
# Delete using "remove_objects"
objects_to_delete = minioClient.list_objects(bucketname, prefix=folderName, recursive=True)
objects_to_delete = [x.object_name for x in objects_to_delete]
for del_err in minioClient.remove_objects(bucketname, objects_to_delete):
print("Deletion Error: {}".format(del_err))
try:
# Use either deleteFolder1 or deleteFolder2
deleteFolder1('test', 'path')
deleteFolder2('test', 'path')
except ResponseError as err:
print(err)
笔记:
deleteFolder1 中 remove_objects 的返回值是一个迭代器。由于该函数是惰性的,默认情况下不会评估。必须评估上面返回的迭代器(例如使用循环),因为它在 deleteFolder1 中完成。
仅当服务对其执行删除操作时出现错误时,迭代器才会包含项目。每个项目都包含有删除错误的对象的错误信息。
您传递给 deleteFunction 的文件夹名称应该是绝对路径,即如果存储桶结构如下test/path/path2并且如果要删除path2文件夹,则需要将path/path2作为文件夹名称传递给 deleteFunction
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