从包含字节数据的字符串中提取字节

Question

我是 python 3 的新手，并试图从包含消息中字符串和字节的字节数组中提取消息。我无法从解码的字节数组中提取字节消息。首先，我解码字节数组。然后我对解码后的数组进行拆分。我在拆分数组时得到字符串值。我尝试使用bytes(v) for v in rest.split()函数尝试获取字节数组，然后对其进行解码，但无法。# The message chunk:chunk = b"1568077849\n522\nb'l5:d4:auth53:\xc3\x99\xc3\xac\x1fH\xc2\xa3ei6eli1eee'\n"# I split the chunk into sub categories for further processing:_, size, rest = (chunk.decode("utf-8")).split('\n', 2)# _ contains "1568077849"# size contains "522" # rest contains "b'l5:d4:auth53:\xc3\x99\xc3\xac\x1fH\xc2\xa3ei6eli1eee'"我应该能够解码其余变量（rest.decode（“utf-8”）），但由于它被存储为字符串，我很难弄清楚如何将其转换为字节和然后解码值。预期结果：l5:d4:auth53:ÙìH£ei6eli1eee

Answer 1

这将打印您的最终结果：

chunk = b"1568077849\n522\nb'l5:d4:auth53:\xc3\x99\xc3\xac\x1fH\xc2\xa3ei6eli1eee'\n"

l1 = chunk.decode('utf-8').split()[2:]  # Initial decode

#  slice out the embedded byte string "b'  '" characters

l1_string = ''.join([x[:-2] if x[0] != 'b' else x[2:] for x in l1])

l1_bytes = l1_string.encode('utf-8')

l1_final = l1_bytes.decode('utf-8')

print('Results')

print(f'l1_string is {l1_string}')

print(f'l1_bytes is {l1_bytes}')

print(f'l1_final is {l1_final}')

Results

l1_string is l5:d4:auth53:ÙìH£ei6eli1ee

l1_bytes is b'l5:d4:auth53:\xc3\x99\xc3\xacH\xc2\xa3ei6eli1ee'

l1_final is l5:d4:auth53:ÙìH£ei6eli1ee

Answer 2

我能够通过这种方式获得预期的输出：

 _, size, rest = (chunk.decode("utf-8")).split('\n', 2)

 rest = bytes(rest.replace("b'", "").replace("'", ""), "utf-8").decode("unicode_escape")