如下的XXXXXXXXXXXXX这个地方怎么放逻辑语句进去呀？

Question

我想实现一个功能，A __a___ ，__m___用户看见A这个名词，输入其后的文本框b一个数字，c处给出逻辑判断的结果比如说，用户输入b=3，如果b<1则在m处显示0，如果b>=1则显示1.我写的程序是这样的：from tkinter import *from tkinter import ttkdef calculate(*args):value = float(A.get())meters.set(if XXXXXXXXXXXXXXX)root = Tk()root.title("example")mainframe = ttk.Frame(root, padding="3 3 12 12")mainframe.grid(column=0, row=0, sticky=(N, W, E, S))mainframe.columnconfigure(0, weight=1)mainframe.rowconfigure(0, weight=1)A = StringVar()feet_entryA = ttk.Entry(mainframe, width=7, textvariable=A)feet_entryA.grid(column=2, row=1, sticky=(W, E))entryA = ttk.Entry(mainframe, width=7, textvariable=A)entryA.grid(column=2, row=1, sticky=(W, E))ttk.Label(mainframe, text="A").grid(column=1, row=1, sticky=E)root.bind('<Return>', calculate)ttk.Label(mainframe, textvariable=meters).grid(column=6, row=5, sticky=(W, E))ttk.Button(mainframe, text="Calculate", command=calculate).grid(column=6, row=6, sticky=W)

Answer 1

from tkinter import *
from tkinter import ttk

def calculate(*args):
value = float(A.get())
meters.set(1 if value >= 1 else 0)

root = Tk()
root.title("example")

mainframe = ttk.Frame(root, padding="3 3 12 12")
mainframe.grid(column=0, row=0, sticky=(N, W, E, S))
mainframe.columnconfigure(0, weight=1)
mainframe.rowconfigure(0, weight=1)

A = StringVar()
feet_entryA = ttk.Entry(mainframe, width=7, textvariable=A)
feet_entryA.grid(column=2, row=1, sticky=(W, E))

entryA = ttk.Entry(mainframe, width=7, textvariable=A)
entryA.grid(column=2, row=1, sticky=(W, E))

ttk.Label(mainframe, text="A").grid(column=1, row=1, sticky=E)

entryA.bind('<Return>', calculate)
meters = StringVar()
ttk.Label(mainframe, textvariable=meters).grid(column=6, row=5, sticky=(W, E))
ttk.Button(mainframe, text="Calculate", command=calculate).grid(column=6, row=6, sticky=W)
root.mainloop()