追加和替换一个字符串中的对象

Question

我正在编写一个文本编码器/加密器（全部由我自己），但我不明白如何在字符串中附加和替换字符：-/代码：import os, sys, randomdig = 0text_encoded = ""text = ""try:    if os.path.isfile(sys.argv[1]) == True:        with open(sys.argv[1], "r") as text:            text = text.readlines()except:    passif text == "":    print("Write the text to encode")    text = input()text = text.split()for _ in range(len(text)):    text_encoded = text[dig].replace("qwertyuiopasdfghjklzxcvbnm ", "mnbvcxzlkjhgfdsapoiuytrewq@")    dig = dig+1print("Your encoded text is:\n"+text_encoded)这是一些输出：Write the text to encodelo lolo lol lolYour encoded text is:lol如果你能以任何方式帮助我，谢谢:-)

Answer 1

如果我没听错，你想用 m 替换 q，用 n 替换 w 等等。尝试以下

import os, sys, random

dig = 0

text_encoded = ""

text = ""

try:

    if os.path.isfile(sys.argv[1]) == True:

        with open(sys.argv[1], "r") as text:

            text = text.readlines()

except:

    pass

if text == "":

    print("Write the text to encode")

    text = input()

mychars=list("qwertyuiopasdfghjklzxcvbnm ")

myencode=list("mnbvcxzlkjhgfdsapoiuytrewq@")

charmap=zip(mychars,myencode)

_map = dict(charmap)

encoded_text = ''.join(_map.get(c) for c in text)

print("Your encoded text is:\n"+encoded_text)

您问题中的字符串提到您想用@替换''。如果您不想这样做，只需从上述两个字符串中删除最后一个字符。

Answer 2

或者你可以使用str.translate

import os, sys, random

from pathlib import Path

TEXT_MAP = ("qwertyuiopasdfghjklzxcvbnm ", "mnbvcxzlkjhgfdsapoiuytrewq@")

def main():

    text = ''

    if len(sys.argv) > 1:

        fname = sys.argv[1]

        p = Path(fname)

        if p.is_file():

            text = p.read_text().strip()

            print(f'Text from {p} is: {text}')

    if not text:

        text = input("Write the text to encode: ").strip()

    trantab = str.maketrans(*TEXT_MAP)

    text_encoded = text.translate(trantab)

    print("Your encoded text is:\n"+text_encoded)

if __name__ == '__main__':

    main()

Answer 3

有两个列表而不是字符串，例如 from_ = "abc".split() 和 to_ = "def".split() 在 from_ 中查找您的字符并获取索引，从 to_ 获取相同的索引字符并将其拼接到一个新的句子。

example:

from_ = "abc".split()

to_ = "def".split()

old_msg = "ab ab"

new_msg = ""

for each in old_msg.split():

    new_msg = new_msg + to_[from_.index(each)]

希望这会有所帮助，请添加缺少的字符处理和任何其他边缘情况