如何将 json_encode 返回的对象转换为 javascript 变量

Question

我正在将一个json_encode对象返回给 ajax 调用。首先，有没有更好的方法来做到这一点？这是json_encode needed?到我问题的根源。当我尝试将键设为变量时，它会引发“未定义错误”。这一行：var displayTriggers = trigger_rows;有谁看到我做错了什么？PHP：try {    $con = getConfig('pdo');    $con->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);    $sql_triggers = "        SELECT *        FROM triggers    ";    $triggers_stmt = $con->prepare($sql_triggers);    $triggers_stmt->execute();    $triggers_rows = $triggers_stmt->fetchAll(PDO::FETCH_ASSOC);    $triggers_arr = array();    foreach ($triggers_rows as $triggers_row) {        $trigger_id = $triggers_row['id'];        $trigger_title = $triggers_row['trigger_name'];        $trigger_setting = $triggers_row['setting'];        $trigger_user = $triggers_row['user_id'];        $trigger_placement = $triggers_row['placement'];        $trigger_date = $triggers_row['date_changed'];        $trigger_active = ( $trigger_setting == '1' ) ? ' active' : '';        $html = '';        $html .= '<div class="triggerRow" data-placement="'.$trigger_placement.'">';        $html .= '<div class="triggerRowLeft">';        $html .= '<div class="triggerTitle">' . $trigger_title . '</div>';        $html .= '<div class="triggerText">' . $trigger_date . '</div>';        $html .= '<div class="triggerText">' . $trigger_user . '</div>';        $html .= '</div>';        $html .= '<div class="triggerRowRight">';        $html .= '<div class="triggerButton' . $trigger_active . '"></div>';        $html .= '</div>';        $html .= '</div>';        $data = array('html' => $html);        $triggers_arr[] = $data;    }    echo json_encode(['trigger_rows' => $triggers_arr]);}catch(PDOException $e) {    echo "Connection failed: " . $e->getMessage();}

Answer 1

var displayTriggers = data.trigger_rows;

应该做的伎俩