在另一个中转换字符串结构

Question

我有一个带有这种模式的文件：[account.invoice.set_num]job_size = 0trans_size = 100[commission.invoice_second.create_full]j_size = 0[commission.invoice_principal.finalize]j_size = 12in_directory = /to/the/directory我想将此模式转换为如下文本：ACCOUNT_INVOICE_SET_NUM_JOB_SIZE = 0ACCOUNT_INVOICE_SET_NUM_TRANS_SIZE = 100COMMISSION_INVOICE_SECOND_CREATE_FULL_J_SIZE=0COMMISSION_INVOICE_PRINCIPALE_FINALIZE_J_SIZE=12 COMMISSION_INVOICE_PRINCIPALE_FINALIZE_IN_DIRECTORY=/to/the/directory我尝试在 Bash unix 或 Python 中做到这一点。我不知道什么是最好/最简单的方法。

Answer 1

使用config.ConfigParser功能非常可行：

from configparser import ConfigParser

config = ConfigParser()

config.read('yourfile')

config_lines = ''

for section in config.sections():

    s_key = section.replace('.', '_')   # transformed section key

    for k, v in config.items(section):

        config_lines += f'{s_key}_{k}'.upper() + f'={v}\n'

print(config_lines)

输出：

ACCOUNT_INVOICE_SET_NUM_JOB_SIZE=0

ACCOUNT_INVOICE_SET_NUM_TRANS_SIZE=100

COMMISSION_INVOICE_SECOND_CREATE_FULL_J_SIZE=0

COMMISSION_INVOICE_PRINCIPAL_FINALIZE_J_SIZE=12

COMMISSION_INVOICE_PRINCIPAL_FINALIZE_IN_DIRECTORY=/to/the/directory