在 PHP 中删除 HTML 属性

Question

我有一个这样的 HTML 代码：<figure id="attachment_83" aria-describedby="caption-attachment-83" style="width: 300px" class="wp-caption alignnone">    <img class="size-medium wp-image-83" src="https://sampleonly.com/wp-content/uploads/2020/01/my-picture-300x169.jpg"        alt="" width="300" height="169"        srcset="https://sampleonly.com/wp-content/uploads/2020/01/my-picture-300x169.jpg 300w, https://sampleonly.com/wp-content/uploads/2020/01/my-picture-1024x576.jpg 1024w, https://sampleonly.com/wp-content/uploads/2020/01/my-picture-768x432.jpg 768w, https://sampleonly.com/wp-content/uploads/2020/01/my-picture-1536x864.jpg 1536w, https://sampleonly.com/wp-content/uploads/2020/01/my-picture-1218x685.jpg 1218w, https://sampleonly.com/wp-content/uploads/2020/01/my-picture.jpg 1920w"        sizes="(max-width: 300px) 100vw, 300px" />    <figcaption id="caption-attachment-83" class="wp-caption-text">This is my picture text.</figcaption><figure>我想删除 id、style、class 等。最终代码如下：<figure>    <img src="https://sampleonly.com/wp-content/uploads/2020/01/my-picture.jpg"/>    <figcaption>This is my picture text.</figcaption><figure>有人可以帮我吗？谢谢你。

Answer 1

这是 preg 替换，您可以使用它来删除所需属性以外的属性。

$html = preg_replace("/(<img\\s)[^>]*(src=\\S+)[^>]*(\\/?>)/i", "$1$2$3", $html);

$html = preg_replace("/(<figure\\s)[^>]*[^>]*(\\/?>)/i", "$1$2$3", $html);

$html = preg_replace("/(<figcaption\\s)[^>]*[^>]*(\\/?>)/i", "$1$2$3", $html);

这会给你输出

<figure ><img src="https://sampleonly.com/wp-content/uploads/2020/01/my-picture-300x169.jpg"><figcaption >This is my picture text.</figcaption><figure>

Answer 2

您可以使用以下代码注意：如果您包含 jquery，则仅使用脚本，否则使用下面的 jquery 链接

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>

    <script>

        $('figure,figcaption,img').removeAttr("id style class height width sizes   srcset aria-describedby");

    </script>