我得到了一个这样的数组：rows: [ [ { title: 'Test', value: 1 }, { title: 'Test2', value: 2 }, { title: 'Test3', value: 3 }, ], [ { title: 'Test4', value: 4 }, { title: 'Test5', value: 5 }, ], [ { title: 'Test6', value: 6 }, { title: 'Test7', value: 7 }, ]]现在我想在每个嵌套对象中取消设置键。value目前我正在做：rows.map(function(fields){ return fields.map(function(field){ field.value = ''; return field; })});你看到更好的方法来做到这一点吗？
3 回答
慕桂英546537
TA贡献1848条经验 获得超10个赞
function deleteKeyFromObject(inputObject) {
for (let[currentObjectKey,currentObjectValue] of Object.entries(inputObject)) {
if (currentObjectKey === 'value') {
delete inputObject.value;
} else if (Array.isArray(currentObjectValue)) {
deleteObjectFromArray(currentObjectValue);
} else if (typeof currentObjectValue === 'object') {
deleteKeyFromObject(currentObjectValue);
}
}
;
}
function deleteObjectFromArray(inputArray) {
for (let currentIndex = 0; currentIndex < inputArray.length; currentIndex++) {
let currentElement = inputArray[currentIndex];
if (Array.isArray(currentElement)) {
deleteObjectFromArray(currentElement);
} else if (typeof currentElement === 'object') {
deleteKeyFromObject(currentElement);
}
}
;
}
var data1 = {
rows: [[{
title: 'Test',
value: 1
}, {
title: 'Test2',
value: 2
}, {
title: 'Test3',
value: 3
}, ], [{
title: 'Test4',
value: 4
}, {
title: 'Test5',
value: 5
}, ], [{
title: 'Test6',
value: 6
}, {
title: 'Test7',
value: 7
}, ]]
}
deleteKeyFromObject(data1);
console.log(data1);
翻过高山走不出你
TA贡献1875条经验 获得超3个赞
可能不修改现有对象可能是更好的做法：
rows = rows.map(fields => {
return fields.map(field => {
return {...field, value: ''};
})
});
慕斯709654
TA贡献1840条经验 获得超5个赞
可用于显式删除属性及其值。无需地图：delete
var ob = {foo:'bar',fizz:'buzz'};
console.log(ob); // Object { foo: "bar", fizz: "buzz" }
delete ob.fizz;
console.log(ob); // Object { foo: "bar" }
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