貌似溢出了 ，请问如何解决？

Question

下面是代码子函数visit中貌似有错编译时能通过但运行时会出错，要我调试但我找不出到底是什么错误#include <stdio.h>typedef struct node{int date;struct node *next;}lstack;void init(lstack *s){s = (lstack *)malloc(sizeof(lstack));s->next = NULL;}int push(lstack *s,int e){lstack *p;p = (lstack *)malloc(sizeof(lstack));p->date = e;p->next = s->next;s->next = p;return 1;}int pop(lstack *s){lstack *p;int e;if(s->next == NULL){printf("栈已空!");return 0;}p = s->next;e = p->date;s->next = p->next;printf("出战成功!\n");free(p);return 1;}int get(lstack *s){int e;if(s->next == NULL){printf("栈已空!");return 0;}e = s->next->date;return e;}void visit(lstack *s){lstack *p = s->next;while(p != NULL){printf("%d\n",p->date);p = p->next;}}int main(){int e = 0;lstack s;init(&s);push(&s,1);push(&s,2);push(&s,3);push(&s,4);e = get(&s);printf("栈顶元素为:%d\n",e);pop(&s);e = get(&s);printf("栈顶元素为:%d\n",e);visit(&s);}

Answer 1

#include <stdio.h>
#include <stdlib.h>
typedef struct node
{
int date;
struct node *next;
}lstack;

void init(lstack *s)
{
s->date = 0;
s->next = NULL;
}

int push(lstack *s,int e)
{
lstack *p;
p = (lstack *)malloc(sizeof(lstack));
p->date = e;
p->next = s->next;
s->next = p;
return 1;
}

int pop(lstack *s)
{
lstack *p;
int e;
if(s->next == NULL)
{
printf("栈已空!");
return 0;
}
p = s->next;
e = p->date;
s->next = p->next;
printf("出战成功!\n");
free(p);
return 1;
}

int get(lstack *s)
{
int e;
if(s->next == NULL)
{
printf("栈已空!");
return 0;
}
e = s->next->date;
return e;
}

void visit(lstack *s)
{
lstack *p = s->next;
while(p != NULL)
{
printf("%d\n",p->date);
p = p->next;
}
}

int main()
{
int e = 0;
lstack s;
init(&s);
push(&s,1);
push(&s,2);
push(&s,3);
push(&s,4);
e = get(&s);
printf("栈顶元素为:%d\n",e);
pop(&s);
e = get(&s);
printf("栈顶元素为:%d\n",e);
visit(&s);
}

Answer 2

不用init()
把
lstack s;
init(&s);
两句换成
lstack s = {0,NULL};
就没问题
调试知
init()函数返回后
结构体中s.next不为空
导致visit（）溢出