如何解决学生标记仪表板的各种问题 - 我们不能在python中使用简单的代码来解决这个问题吗..？

Question

考虑两个列表中给出的班级学生的分数列表Students = ['student1','student2','student3','student4','student5','student6','student7','student8','student9','student10']Marks = [45, 78, 12, 14, 48, 43, 45, 98, 35, 80]从上面两个列表中，学生[0]得到分数[0]，学生[1]得到分数[1]等等 谁得到的分数介于>25百分位<75百分位之间，按分数的递增顺序排列我的问题 - 我们不能在python中使用简单的代码来解决这个问题吗？？我已经写了代码，直到这里。要查找数字>25 和 <75，但无法按升序排列。Sort（） 不起作用，排序也不工作。请帮助如何提取特定的数组值并分配给另一个数组来解决此问题。for i in range(0,10):    if Marks[i]>25 and Marks[i]<75:         print(Students[i],Marks[i])        print(i)

Answer 1

对代码进行少量添加即可解决此问题，以下是解决方案

Students = ['student1','student2','student3','student4','student5','student6','student7','student8','student9','student10']

Marks = [45, 78, 12, 14, 48, 43, 45, 98, 35, 80]

Students,Marks=zip(*sorted(zip(Students, Marks))) #addition to your code

for i in range(0,10):

    if Marks[i]>25 and Marks[i]<75: 

        print(Students[i],Marks[i])

Answer 2

看起来@Green斗篷人的答案是正确的。但无论如何，如果你想要的是获取两个范围之间有分数的学生的数据，我会这样做：

# Get a dict of students with it's mark, filtered by those with mark between 25 and 75

students_mark = {s: m for s, m in zip(Students, Marks) if m > 25 and m < 75}

# Sort results

res = dict(sorted(students_mark.items(), key=lambda i: i[1])

# res: {'student9': 35, 'student6': 43, 'student1': 45, 'student7': 45, 'student5': 48}

# In one line

res = {s: m for s, m in sorted(zip(Students, Marks), key=lambda i: i[1]) if m > 25 and m < 75}

总结一下：首先将每个学生与它的分数联系起来，然后进行过滤和排序。我将结果存储为字典，因为它似乎更方便。

Answer 3

第25百分位是“拿走东西的人中倒数第四”，第75百分位是“前四”，无论实际得分如何。因此，您需要做的是对列表进行排序，然后根据索引从中间取出一个切片。

以下是我认为您正在尝试执行的操作：

import math

students = ['student1','student2','student3','student4','student5','student6','student7','student8','student9','student10']

marks = [45, 78, 12, 14, 48, 43, 45, 98, 35, 80]

# zip() will bind together corresponding elements of students and marks

# e.g. [('student1', 45), ('student2', 78), ...]

grades = list(zip(students, marks))

# once that's all in one list of 2-tuples, sort it by calling .sort() or using sorted()

# give it a "key", which specifies what criteria it should sort on

# in this case, it should sort on the mark, so the second element (index 1) of the tuple

grades.sort(key=lambda e:e[1])

# [('student3', 12), ('student4', 14), ('student9', 35), ('student6', 43), ('student1', 45), ('student7', 45), ('student5', 48), ('student2', 78), ('student10', 80), ('student8', 98)]

# now, just slice out the 25th and 75th percentile based on the length of that list

twentyfifth = math.ceil(len(grades) / 4)

seventyfifth = math.floor(3 * len(grades) / 4)

middle = grades[twentyfifth : seventyfifth]

print(middle)

# [('student6', 43), ('student1', 45), ('student7', 45), ('student5', 48)]

你这里有10名学生，所以你如何舍入取决于你（我选择通过舍入“向内”来严格包括那些严格在25-75百分位内的学生 - 你可以通过切换和来做相反的事情，并让你的最终列表在这种情况下再有两个元素 - 或者你可以以相同的方式四舍五入它们）。twentyfifthseventyfifthceilfloor