在 GRPC 中处理 IO 等待状态的优雅方式

Question

我们的服务器（grpc-gateway + grpc）在K8S上运行，使用go 1.13，并终止堆栈信息    Last State:    Terminated      Reason:      Error      Message:     o.(*Reader).fill(0xc002ec78c0)                   /Users/local/go/src/bufio/bufio.go:100 +0x103bufio.(*Reader).Peek(0xc002ec78c0, 0x4, 0x0, 0x0, 0x0, 0x0, 0xc002e79ad0)  /Users/local/go/src/bufio/bufio.go:138 +0x4fnet/http.(*conn).readRequest(0xc00245a000, 0x1ef4800, 0xc000be7780, 0x0, 0x0, 0x0)  /Users/local/go/src/net/http/server.go:962 +0xb3bnet/http.(*conn).serve(0xc00245a000, 0x1ef4800, 0xc000be7780)  /Users/local/go/src/net/http/server.go:1817 +0x6d4created by net/http.(*Server).Serve  /Users/local/go/src/net/http/server.go:2928 +0x384goroutine 8724981 [IO wait]:internal/poll.runtime_pollWait(0x7f5d3a8f84e8, 0x72, 0xffffffffffffffff)  /Users/local/go/src/runtime/netpoll.go:184 +0x55internal/poll.(*pollDesc).wait(0xc000155d98, 0x72, 0x1000, 0x1000, 0xffffffffffffffff)  /Users/local/go/src/internal/poll/fd_poll_runtime.go:87 +0x45internal/poll.(*pollDesc).waitRead(...)  /Users/local/go/src/internal/poll/fd_poll_runtime.go:92internal/poll.(*FD).Read(0xc000155d80, 0xc00138b000, 0x1000, 0x1000, 0x0, 0x0, 0x0)  /Users/local/go/src/internal/poll/fd_unix.go:169 +0x1cfnet.(*netFD).Read(0xc000155d80, 0xc00138b000, 0x1000, 0x1000, 0xc00142b9e8, 0x4ce13d, 0xc000155d80)  /Users/local/go/src/net/fd_unix.go:202 +0x4fnet.(*conn).Read(0xc0000dd690, 0xc00138b000, 0x1000, 0x1000, 0x0, 0x0, 0x0)  /Users/local/go/src/net/net.go:184 +0x68net/http.(*connReader).Read(0xc001e9b050, 0xc00138b000, 0x1000, 0x1000, 0x0, 0x0, 0x0)  /Users/local/go/src/net/http/server.go:785 +0xf4bufio.(*Reader).fill(0xc0021fe060)      Exit Code:    2根据这个问题，一个可能的解决方案是>  s := new(http.Server)>  // ...>  s.ReadTimeout = 5 * time.Second>  s.WriteTimeout = 5 * time.Second>  // ...但是，我们未能找到来自，我们错过了什么吗？或者如何在GRPC中更优雅地处理IO等待状态下的goroutine？ReadTimeoutgrpc.NewServergrpc 版本是v1.21.1

Answer 1

网易娱乐.NewServer 允许在创建期间使用零个或多个：ServerOption

func NewServer(opt ...ServerOption) *Server

虽然似乎没有一个或等价物，你可以试试：ReadTimeoutWriteTimeouthttp.Serverkeepalive.ServerParameters

type ServerParameters struct {

    MaxConnectionIdle     time.Duration // The current default value is infinity.

    MaxConnectionAge      time.Duration // The current default value is infinity.

    MaxConnectionAgeGrace time.Duration // The current default value is infinity.

    Time                  time.Duration // The current default value is 2 hours.

    Timeout               time.Duration // The current default value is 20 seconds.

}

（完整的文档保持。服务器参数)

并调整为低于 2 小时的内容：keepalive.ServerParameters.Time

srv := grpc.NewServer(

    keepalive.ServerParameters{Time:5*time.Minute},

)

这将降低连接重用率 - 但也会释放早已失效的客户端连接。

Answer 2

使用具有超时的上下文。

https://golang.org/pkg/context/