如何根据流中的元素动态划分连续的 RXJava 流？

Question

最简单的例子是像这样的字符串流：["3", "a", "b", "c", "1", "a", "2", "a", "b"]数字表示它的组应该包含多少个元素。非常重要的一点是，流是连续的，所以我们不能只是等待下一个数字来分割流。据我所知，RXJava2中没有内置功能var flowable = Flowable.concat(Flowable.fromArray("3", "a", "b", "c", "1", "a", "2", "a", "b"), Flowable.never());flowable/*Something here*/.blockingSubscribe(System.out::println);预期的输出将是：[3, a, b, c][1, a][2, a, b]

Answer 1

我后来发现了阿卡诺克的RxJava2扩展包。使用它，我能够构建这个，它可以做我想要的：

var flowable = Flowable.concat(Flowable.fromArray("3", "a", "b", "c", "1", "a", "2", "a", "b"), Flowable.never());

flowable.compose(FlowableTransformers.bufferUntil(new Predicate<>() {

    private int remaining = 0;

    @Override

    public boolean test(String next) {

        if(next.chars().allMatch(Character::isDigit)) {

            remaining = Integer.parseInt(next);

        }

        return --remaining < 0;

    }

})).blockingSubscribe(System.out::println);